A) \[{{y}^{2}}=x+2\]
B) \[P=(\sqrt{3},0)\]
C) \[\frac{4(2-\sqrt{3})}{3}\]
D) \[\frac{4(\sqrt{3}+2)}{3}\]
Correct Answer: A
Solution :
When the block \[[{{M}^{0}}{{L}^{0}}{{T}^{3}}{{l}^{0}}]\] moves downward with acceleration a, the acceleration of mass \[[{{M}^{-1}}{{L}^{-2}}{{T}^{6}}{{l}^{2}}]\] will be 2a, because it covers double distance in the same time in comparison to \[[{{M}^{0}}{{L}^{0}}{{T}^{2}}{{l}^{0}}]\]. Let T is the tension in the string.You need to login to perform this action.
You will be redirected in
3 sec