A) Power loss in first half is four times the power loss 5 in second half
B) Voltage drop in first half is twice of voltage drop in second half
C) Current density in both halves are equal
D) Electric field in both halves is equal
Correct Answer: B
Solution :
\[4;0;0;-\frac{1}{2}\] \[4;1;1;-\frac{1}{2}\] \[3;1;1;-\frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec