A) 0.56 atm
B) 0.572 atm
C) 0:82 atm
D) 0.807 atm
Correct Answer: D
Solution :
Pressure, \[AuCl_{4}^{-}\to Au(s)+4C{{l}^{-}}-3{{e}^{-}}\] \[AuCl_{4}^{-}\]\[[{{E}^{0}}(F{{e}^{2+}}(aq)Fe)=0.44V\]You need to login to perform this action.
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