A) I and II
B) II and III
C) I and III
D) I, II and III
Correct Answer: D
Solution :
I.\[\frac{n(n-5)}{12}\] It is a redox reaction but not a disproportionation reaction. Since, different N-species are involved. II.\[\frac{20!}{4!\times 5!}\]same as (I) III. \[\frac{20!}{{{4}^{5}}}\] Thus, it is also not a disproportionation reaction.You need to login to perform this action.
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