A) 22.40 mL
B) 33.40 mL
C) 55.40 mL
D) 66.40 mL
Correct Answer: D
Solution :
Mass of X decay =0.75 g Moles of X decayed \[\text{ }\!\!\pi\!\!\text{ -}\] = moles of He formed \[\text{ }\!\!\pi\!\!\text{ -}\]of He at \[a=\cos \frac{2\pi }{7}+i\sin \frac{2\pi }{7},\]\[\alpha =a+{{a}^{2}}+{{a}^{4}}\]You need to login to perform this action.
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