A) 1
B) 3
C) 2
D) 3/2
Correct Answer: C
Solution :
\[{{x}_{1}}.{{x}_{2}}.{{x}_{3}}...\]\[9{{x}^{2}}-18\text{ }\!\!|\!\!\text{ x }\!\!|\!\!\text{ }+5=0\]and \[{{\log }_{e}}\] \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}y,\]i.e.\[\frac{dy}{dx}\]ratio of \[\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}-{{2}^{y}}}\]for the maixture\[\frac{{{2}^{x}}+{{2}^{y}}}{1+{{2}^{x+y}}}\] and\[{{2}^{x-y}}\left( \frac{{{2}^{y}}-1}{1-{{2}^{x}}} \right)\] \[\frac{{{2}^{x-y}}-{{2}^{x}}}{{{2}^{y}}}\]\[x-3y=0\] \[x+3y=0\]\[3x-y=0\] \[2x+y=0\]\[\sin A+\cos A=m\] \[{{\sin }^{3}}A+{{\cos }^{3}}A=n,\]n=2You need to login to perform this action.
You will be redirected in
3 sec