A) -72 kcal
B) -28 kcal
C) +28kcal
D) +72kcal
Correct Answer: D
Solution :
\[x-y+1=0\] \[(p\to \tilde{\ }p\wedge )(\tilde{\ }p\to p)\]Therefore, weight of solute = 480 g \[\frac{6!}{3!}\]The activation energy for the forward reaction = 50 kcal \[\underset{x\to -1}{\mathop{\lim }}\,\left( \frac{{{x}^{4}}+{{x}^{2}}=x+1}{{{x}^{2}}-x+1} \right)\frac{1-\cos (x+1)}{{{(x+1)}^{2}}}\]The activation energy for the backward reaction = 50 + 72 = + 72 kcalYou need to login to perform this action.
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