A) 0.1
B) 0.4
C) 0.3
D) 0.2
Correct Answer: B
Solution :
\[y={{\log }_{e}}(x)+C\] Molar concentration of \[y={{({{\log }_{e}}x)}^{2}}+C\] In equilibrium state, when it 50% dissociates \[y=\pm \sqrt{{{\log }_{e}}x{{)}^{2}}+2C}\] \[xy={{x}^{y}}+C\] Now, from\[\frac{4}{{{100}^{3}}}\] \[\frac{3}{{{50}^{3}}}\]You need to login to perform this action.
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