A) one point
B) three points
C) two points
D) four points
Correct Answer: D
Solution :
Clearly, A is the set of all points on the circle \[f(x)=\frac{\sin ({{e}^{x-2}}-1)}{\log (x-1)},\]and B is the set of all points on the ellipse \[\underset{x\to 2}{\mathop{\lim }}\,f(x)\]These two intersect at four points P, Q, R and S. Hence, \[{{x}^{2}}-ax+b=0,\]contains four points.You need to login to perform this action.
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