A) increasing on \[\frac{x+y}{x-y}=\frac{5}{2},\]
B) decreasing on R
C) increasing on R
D) decreasing on \[\frac{x}{y}\]
Correct Answer: A
Solution :
We have,\[a{{x}^{2}}+2hxy+b{{y}^{2}}=1,a>0\] On differentiating both sides w.r.t. x, we get \[\frac{\pi }{4}\] \[f(x)=x{{e}^{-x}}\]\[[0,\infty ),\] \[0\]\[\frac{1}{e}\] Since, \[\theta \] for all x. Therefore, signs of f'(x) for different values of x are as shown below: Clearly, f{x) is increasing on \[\frac{\pi }{6}\] and decreasing on\[\frac{\pi }{4}\]You need to login to perform this action.
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