A) \[y-1=0\]
B) \[x-1=0\]
C) \[x+y-1=0\]
D) \[x-y+1=0\]
Correct Answer: B
Solution :
Let x be the desired length. Potential gradient in the first case \[\frac{5}{3}\] \[\frac{3}{5}\] ...(i) Potential gradient in the second case. \[6\frac{2}{3}%\] \[U=k\left[ \frac{2q(8d)}{r}-\frac{(2q)(q)}{x}-\frac{(8q)(q)}{r-x} \right]\]\[k=\frac{1}{4\pi {{\varepsilon }_{0}}}\] ?(ii) From Eqs. (i) and (ii), we get\[\frac{2}{x}+\frac{8}{r-x}\] \[\frac{2}{x}+\frac{8}{r-x}=y\]\[\frac{dy}{dx}=0\]You need to login to perform this action.
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