A) 20
B) 22
C) 24
D) 26
Correct Answer: A
Solution :
Path difference at P is \[1.96\times {{10}^{-20}}\] For intensity to be maximum \[\Omega \] \[\Omega \]\[\frac{i}{{{i}_{0}}}=\frac{4}{11}\] (n = 0, 1,???) \[\frac{i}{{{i}_{0}}}=\frac{3}{11}\] \[\frac{i}{{{i}_{0}}}=\frac{2}{10}\]\[\frac{i}{{{i}_{0}}}=\frac{1}{11}\] \[\sqrt{2}\]\[4R\Omega .\] Substituting \[{{w}_{1}}\]\[{{w}_{2}}\]or n = 1, 2, 3, 4, 5,..... Therefore, in all four quadrants, there can be 20 maxim as. There are more maxim as at \[\frac{-({{w}_{2}}-{{w}_{1}})}{5Rt}\] and \[\frac{-n({{w}_{2}}-{{w}_{1}})}{5Rt}\] But a = 5 corresponds to \[\frac{-n({{w}_{2}}-{{w}_{1}})}{Rnt}\]and \[\frac{-n({{w}_{2}}-{{w}_{1}})}{Rt}\]which are coming only twice. While we have multiplied it four times. Therefore, total number of maxim as still 20.You need to login to perform this action.
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