question_answer

A small block of wood of specific gravity 0.5 is submerged at a depth of 1.2 m in a vessel filled with the water. The vessel is accelerated upwards with an acceleration \[\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}-{{2}^{y}}}\] Time taken by the block to reach the surface, if it is released with zero initial velocity is

A)  0.6 s                     

B)  0.4 s

C) 1.2s                       

D) 1 s

Correct Answer: B

Solution :

Let m be the mass of block and a its acceleration in upward direction. Then, \[C{{l}^{-}}>SO_{4}^{2-}>C{{l}^{-}}\] \[A{{l}^{3+}}>B{{a}^{2+}}>N{{a}^{+}}\]\[_{88}^{228}X-3\alpha ,-\beta \xrightarrow[{}]{{}}Y.\] \[_{82}^{216}Pb\]\[_{82}^{217}Pb\] Acceleration of block relative to water \[_{83}^{218}Bi\] \[_{83}^{216}Bi\]\[NC{{l}_{3}}\] \[N{{H}_{3}}\]\[HCl{{O}_{4}}\] \[HCl{{O}_{3}}\]\[HOCl\]