A) 7m
B) 7.29m
C) 6.06 m
D) 8.55 m
Correct Answer: C
Solution :
(c) From Snell's law, \[6.60\times {{10}^{-23}}g\] \[3.30\times {{10}^{-23}}g\]\[2.20\times {{10}^{-23}}g\] \[13.20\times {{10}^{-23}}g\]\[({{m}_{p}}=1.6\times {{10}^{-27}}kg)\] This means that the ray becomes parallel to side AD inside the slab. This implies for the second face \[{{10}^{20}}kg/{{m}^{3}}\] Given R = 0.4 m \[{{10}^{17}}kg/{{m}^{3}}\] \[{{10}^{14}}kg/{{m}^{3}}\]\[{{10}^{11}}kg/{{m}^{3}}\] \[\alpha ={{\tan }^{-1}}\left( \frac{1}{5} \right).\] \[a=2m{{s}^{-2}}.\]upto 2 decimal places)You need to login to perform this action.
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