A) 10 mA
B) 3.33 mA
C) 6.67 mA
D) 0 mA
Correct Answer: B
Solution :
The voltage drop across \[\tan \theta \le 3{{\mu }_{s}}\]is \[\tan \theta <3{{\mu }_{s}}\] The current through \[{{R}^{1/2}}\] is \[{{R}^{3/2}}\] \[{{R}^{-1/2}}\] The voltage drop across \[{{R}^{0}}\] is \[\sqrt{2}.\] The current through \[h:R\]is \[R:2h\] The current through Zener diode is \[2h:R\]You need to login to perform this action.
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