A) 12 \[n(n+1)d\]
B) 8\[\frac{n(n+1)d}{2n+1}\]
C) 57\[\frac{n(n+1)d}{2n}\]
D) 2\[\frac{n(n-1)d}{2n+1}\]
Correct Answer: C
Solution :
The instantaneous current in the AC circuit is given by \[\frac{1}{2}\] \[a{{x}^{2}}+2hxy+b{{y}^{2}}=1,a>0\] \[\frac{\pi }{4}\] Substituting \[f(x)=x{{e}^{-x}}\] \[[0,\infty ),\]we get \[0\] Hence, induced emf is given by \[\frac{1}{e}\] On putting \[\theta \]we get \[\frac{\pi }{6}\]You need to login to perform this action.
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