A) 10,20,10
B) 15,20, 15
C) 5,15, 20
D) 5,10, 20
Correct Answer: B
Solution :
Time taken by the small ball to return to the hands of the juggler is \[\frac{2}{3}\] So, he is throwing the balls after 1 s each. Let at some instant, he throws the ball number 4. Before 1 s of throwing it, he throws ball 3. So, the height of ball 3 is \[\frac{1}{3}\] \[2x-3y-4=0\] Before 2 s, he throws ball 2. So, the height of ball 2 is \[x+y=1,\] Before 3 s, he throws ball 1. So, the height of ball 1 is \[\sqrt{2}\]\[5\sqrt{2}\]\[\frac{1}{\sqrt{2}}\]You need to login to perform this action.
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