A) \[\left( \frac{1}{2},\frac{1}{2} \right)\]
B) \[\left( \frac{1}{2},\pm \sqrt{2} \right)\]
C) \[{{y}^{2}}-kx+8=0,\]
D) \[\frac{1}{8}\]
Correct Answer: B
Solution :
FBD of m in frame of wedge \[{{\alpha }_{\max }}\] Now,\[{{\sin }^{-1}}\left[ \frac{{{n}_{1}}}{{{n}_{2}}}\cos \left( {{\sin }^{-1}}\left( \frac{{{n}_{2}}}{{{n}_{1}}} \right) \right) \right]\] \[{{\sin }^{-1}}\left[ {{n}_{1}}\cos \left( {{\sin }^{-1}}\left( \frac{1}{2} \right) \right) \right]\]\[{{\sin }^{-1}}\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)\] \[{{\sin }^{-1}}\left( \frac{{{n}_{1}}}{{{n}_{1}}} \right)\]\[\frac{dy}{dt}<0.\]You need to login to perform this action.
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