A) 2.4 J
B) 5.55 J
C) 4,44 J
D) -10 J
Correct Answer: B
Solution :
Maximum frictional force between the slab and the block \[20\Omega \] Evidently, \[\text{ }\!\!\alpha\!\!\text{ -}\] So, the two bodies will move together as a single unit. If a be their combined acceleration, then\[\text{ }\!\!\gamma\!\!\text{ -}\] Therefore, motional force acting can be obtained as\[\alpha \text{-}\] Using \[\alpha \text{-}\] \[\text{ }\!\!\gamma\!\!\text{ -}\]and\[x\left( <<R \right)\] Therefore, work done by friction \[(x=5\lambda )\]\[{{v}_{1}}\]You need to login to perform this action.
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