A) 10.2 N upwards
B) 4.2 N downwards
C) 8.3 N downwards
D) 6.2 N upwards
Correct Answer: C
Solution :
Length of rod inside the water Up thrust, \[{{C}_{3}}{{H}_{6}}O\] \[C{{H}_{3}}COC{{H}_{3}}\]\[{{C}_{2}}{{H}_{5}}CHO\] Weight of rod, w = 20 x 10 = 20 N For rotational equilibrium of rod, net torque about O should be zero. \[C{{H}_{2}}=CH-C{{H}_{2}}-OH\]\[C{{H}_{3}}-O-CH=C{{H}_{2}}\] \[C{{H}_{3}}C{{H}_{2}}I\xrightarrow[{}]{NaCN}A\xrightarrow[Partial\,hydrolysis]{O{{H}^{-}}}\]\[B\xrightarrow[{}]{B{{r}_{2}}/NaOH}C.\]\[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]\[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-NHBr\]\[C{{H}_{3}}C{{H}_{2}}COON{{H}_{4}}\]\[C{{H}_{3}}.C{{H}_{2}}\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-NB{{r}_{2}}\] \[IV<II<III<I\] For vertical equilibrium of rod, force exerted by the hinge on the rod will be \[IV<III<II<I\] downwards i. e. 8.3 N downwardsYou need to login to perform this action.
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