A) 6, 6
B) 6,8
C) 8,8
D) 8,6
Correct Answer: C
Solution :
The coordination number is 8:8 in\[{{(y-2)}^{2}}=(x-1),\] The coordination number is 6:6 in \[x=1+xy\frac{dy}{dx}+\frac{{{(xy)}^{2}}}{2!}+{{\left( \frac{xy}{dx} \right)}^{2}}+\frac{{{(xy)}^{3}}}{3!}{{\left( \frac{dy}{dx} \right)}^{3}}\]You need to login to perform this action.
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