A) \[{{w}_{1}}\]
B) \[{{w}_{2}}\]
C) \[\frac{-({{w}_{2}}-{{w}_{1}})}{5Rt}\]
D) \[\frac{-n({{w}_{2}}-{{w}_{1}})}{5Rt}\]
Correct Answer: D
Solution :
Let\[x=\frac{1}{y}.\]Then, \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left\{ \frac{a_{1}^{1/x}+a_{2}^{1/x}+...+a_{n}^{1/x}}{n} \right\}}^{nx}}\] \[=\underset{y\to 0}{\mathop{\lim }}\,{{\left\{ \frac{a_{1}^{y}+a_{2}^{y}+...+a_{n}^{y}}{n} \right\}}^{n/y}}\] \[=\underset{y\to 0}{\mathop{\lim }}\,{{\left\{ 1+\frac{a_{1}^{y}+a_{2}^{y}+...+a_{n}^{y}-n}{n} \right\}}^{n/y}}\] \[={{e}^{\underset{y\to 0}{\mathop{\lim }}\,}}\left\{ \frac{a_{1}^{y}-1}{y}+\frac{a_{1}^{y}-1}{y}+...+\frac{a_{n}^{y}-1}{y} \right\}\] \[={{e}^{\log {{a}_{1}}+\log {{a}_{2}}+...+\log {{a}_{n}}}}\] \[={{e}^{\log ({{a}_{1}}{{a}_{2}}...{{a}_{n}})}}\] \[={{a}_{1}}{{a}_{2}}{{a}_{3}}...{{a}_{n}}\]You need to login to perform this action.
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