A) 2.5m
B) 5m
C) 7.5m
D) 10m
Correct Answer: D
Solution :
Here: Mass of the cylinder \[m=10\text{ }kg\] Initial velocity of cylinder \[v=10\text{ }m/s\] Coefficient of friction between surface and the cylinder \[\mu =0.5\] The kinetic energy of the cylinder is \[=\frac{1}{2}m{{\upsilon }^{2}}\] \[=\frac{1}{2}\times 10\times {{10}^{2}}\] \[=500kgm/sec\] ...(1) The work done by the cylinder in rolling over the plane is = Force of friction\[\times \]distance \[=\mu mg\times s\] \[=0.5\times 10\times 10\times s\] \[=50s\] ...(2) As the kinetic energy of the cylinder will be consumed in doing the work. Hence, from (1) and (2) \[500=50s\] \[s=\frac{500}{50}=10\,m\]You need to login to perform this action.
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