A) 1.8
B) 48.4
C) 91.8
D) 94.6
Correct Answer: C
Solution :
The density of solution\[=1.8\text{ }g\text{ }ml\] Weight of one litre of solution = 1800 g \[\therefore \] weight of\[{{H}_{2}}S{{O}_{4}}\]in the solution \[=\frac{1800\times 90}{100}\] \[=1620g\] \[\therefore \]weight of solvent \[=1800-1620\] \[=180gm\] \[\therefore \]molality\[=\frac{1620}{98}\times \frac{100}{180}=91.8\]You need to login to perform this action.
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