A) 21
B) 27
C) 38
D) 49
Correct Answer: D
Solution :
The equivalent weight of \[{{H}_{3}}P{{O}_{4}}=\frac{molecular\text{ }weight}{2}\] (molecular wt. of\[{{H}_{3}}P{{O}_{4}}\] \[=3+31+64=98)\] \[=\frac{98}{2}=49\]You need to login to perform this action.
You will be redirected in
3 sec