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Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    At\[25{}^\circ C\]the specific conductivity of a normal solution of\[KCl\]is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:

    A)  0.815             

    B)  1.016

    C)  1.106             

    D)  2.016

    Correct Answer: C

    Solution :

     We know that cell constant \[=\frac{specific\text{ }conductivity}{observed\text{ }conductance}\] Here, specific conductance = 0.002765 observed conductance\[=\frac{1}{R}\] \[=\frac{1}{400}\] \[\therefore \]cell constant\[=0.002765\times 400\] \[=1.106\]


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