A) 40J
B) 20J
C) 80J
D) 60J
Correct Answer: A
Solution :
Potential difference \[V=400\text{ }V\] Charge \[Q=0.2C\] The energy released from the capacitor is given by, \[E=\frac{1}{2}QV=\frac{1}{2}\times 0.2\times 400\] \[=40\,J\]You need to login to perform this action.
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