A) remain same
B) be quadrupled
C) be doubled
D) be halved
Correct Answer: B
Solution :
Here: Initial between two slits \[{{d}_{2}}=\frac{d}{2}\] Final distance between two slits \[{{d}_{2}}=\frac{d}{2}\] Initial distance between slit and screen \[{{D}_{1}}=D\] Final distance between slit and screen \[{{D}_{2}}=2D\] The relation for fringe width is given by \[B\propto \frac{D}{d}\] Force \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{{{D}_{1}}}{{{D}_{2}}}\times \frac{{{d}_{2}}}{{{d}_{1}}}\] \[{{B}_{2}}=4{{B}_{1}}\] Therefore, the fringe width will be four times.
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