A) 300K
B) 900K
C) 600K
D) 1200K
Correct Answer: B
Solution :
We know that kinetic energy\[=\frac{3}{2}RT\] \[R=2cal\] \[T=27+273=300\text{ }K\] By putting the values we have K.E. \[=\frac{3}{2}\times 2\times 300\] \[=900\text{ }K\]You need to login to perform this action.
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