2. Solved Papers
  3. Manipal Medical

Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    A resistance of a galvanometer\[G=6\,\Omega \] maximum current of 2 amp is measured by it. Then required resistance to convert it into an ammeter reading up to 6 A, will be:

    A)  \[5\,\Omega \]            

    B)  \[4\,\Omega \]

    C)  \[3\,\Omega \]            

    D)  \[2\,\Omega \]

    Correct Answer: C

    Solution :

     Here: Resistance of galvanometern \[G=6\,\Omega \] maximum   current   through   the galvanometer \[{{i}_{g}}=2A\] Current in ammeter \[i=6\text{ }A\] The current through galvanometer is given by \[{{i}_{g}}=\frac{S}{S+G}i\] Or \[2=\frac{S}{S+6}\times 6\] or   \[25+12=69\] So,        \[S=3\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner