A) 7.5 cm
B) 6.75 cm
C) 4.5 cm
D) 1.5 cm
Correct Answer: D
Solution :
Here: Actual depth of liquid \[h=6\text{ }cm\] Refactive index of the liquid\[=\frac{4}{3}\] Using the relation \[\mu =\frac{actual\text{ }depth\,(h)}{apparent\text{ }depth\,(x)}\] Or \[x=h\times \frac{3}{4}=6\times \frac{3}{4}=4.5\,m\] Hence, the coin will appear at a depth of \[=6-4.5=1.5\text{ }cm\]You need to login to perform this action.
You will be redirected in
3 sec