A) \[-3.4eV\]
B) \[-6.6eV\]
C) \[-8.1eV\]
D) \[-10.2eV\]
Correct Answer: D
Solution :
Energy of nth orbit of hydrogen atom \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] The energy absorbed/ when an electron jumps from the first energy level\[(n=1)\] to second level\[(n=2)\] \[=-13.6\times \left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] \[=-13.6\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]\] \[=-13.6\times \frac{3}{4}=-10.2\,eV\]You need to login to perform this action.
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