A) 50 ml
B) 5.0 ml
C) 0.50ml
D) 100 ml
Correct Answer: A
Solution :
For complete neutralization, m. eq of\[{{H}_{2}}S{{O}_{4}}=\]m. eq. of\[NaOH\] \[(\because 0.1\,M\,{{H}_{2}}S{{O}_{4}}=0.2\,N\,{{H}_{2}}S{{O}_{4}})\] \[V=50ml\]You need to login to perform this action.
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