A) \[{{T}_{1}}\]was decreased
B) \[{{T}_{1}}\] was increased
C) \[{{T}_{2}}\] was increased
D) \[{{T}_{2}}\] was decreased
Correct Answer: A
Solution :
The relation for frequency and tension is given by\[f\propto \sqrt{T}\] As \[{{T}_{1}}>{{T}_{2}}\] i.e, \[{{f}_{1}}>{{f}_{2}},\] So, \[{{f}_{1}}-{{f}_{2}}=6\,Hz\] when we increase lower tension\[{{T}_{2}},\]then\[{{f}_{2}}\] will be increased and\[{{f}_{1}}\]will, decrease Hence, \[{{f}_{1}}-{{f}_{2}}=6Hz\]You need to login to perform this action.
You will be redirected in
3 sec