A) \[PC{{l}_{3}}\]
B) \[Cl{{F}_{3}}\]
C) \[N{{H}_{3}}\]
D) \[BC{{l}_{3}}\]
Correct Answer: B
Solution :
\[CI{{F}_{3}}\]has\[s{{p}^{3}}d\]hybridization. Out of five\[s{{p}^{3}}d\]hybrid orbitals two are completely filled by\[lp\] and three are half filled which overlap with three\[2{{p}_{z}}\] half-filled orbitals of three F-atoms. Due to the presence of two\[lps\]its geometry is bent T-shaphed. \[\underset{\begin{smallmatrix} | \\ F \end{smallmatrix}}{\overset{\begin{smallmatrix} F \\ | \end{smallmatrix}}{\mathop{\underset{\bullet }{\overset{\bullet }{\mathop{{}_{\bullet }^{\bullet }Cl}}}\,}}}\,-F\]
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