A) 210 s
B) 105 s
C) 420 s
D) 50 s
Correct Answer: A
Solution :
The heat required for producing 1 g of steam = 540 cal \[=540\times 4.2\text{ }J=2268\text{ }J\] Energy given by immersion heater is \[=1.08\text{ }kW=1080\text{ }W\] Now time taken in boiling 100 g of water \[=\frac{2268\times 100}{1080}=210\,\sec \]You need to login to perform this action.
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