A) 30 K
B) 18 K
C) 50 K
D) 42 K
Correct Answer: D
Solution :
In cylinder A heat is supplied at constant pressure while in cylinder B heat is supplied at constant volume. \[\therefore \] \[{{(\Delta Q)}_{A}}=n{{C}_{p}}{{(\Delta T)}_{A}}\] ...(1) and \[{{(\Delta Q)}_{B}}=n{{C}_{V}}{{(\Delta T)}_{B}}\] ...(2) Given: \[{{(\Delta Q)}_{A}}={{(\Delta Q)}_{B}}\] \[\therefore \] \[{{(\Delta T)}_{B}}=\frac{{{C}_{P}}}{{{C}_{V}}}{{(\Delta T)}_{A}}\] \[=1.4\times 30\] \[\left( \because \frac{{{C}_{P}}}{{{C}_{V}}}=1.4 \right)\] \[=42\,K\]You need to login to perform this action.
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