A) 600 mA
B) 700 mA
C) 750 mA
D) 900 mA
Correct Answer: D
Solution :
The current flowing in coil of galvanometer is \[i=k\,\tan \theta \] \[=900\times {{10}^{-3}}\times tan45{}^\circ \] \[=900\times {{10}^{-3}}\] \[=900mA\]You need to login to perform this action.
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