A) 0.053 nm
B) 0.106 nm
C) 0.2116 nm
D) 0.4256 nm
Correct Answer: C
Solution :
Given that: Bohrs orbit of hydrogen atom \[(n)=2\] Atomic number of hydrogen\[\text{(z)}=1\] By using: \[r=\frac{0.529{{n}^{2}}}{z}\] \[=\frac{0.529\times {{(2)}^{2}}}{1}\] \[=\frac{0.529\times 4}{1}\] \[=2.116\overset{o}{\mathop{\text{A}}}\,\] \[=0.2116\text{ }nm\]You need to login to perform this action.
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