A) \[\frac{2\upsilon (n-1)}{n}\]
B) \[\frac{\upsilon (n-1)}{n}\]
C) \[\frac{\upsilon (n+1)}{n}\]
D) \[\frac{2\upsilon (n+1)}{n}\]
Correct Answer: A
Solution :
Displacement in last 2 second \[=\frac{1}{2}a{{n}^{2}}-\frac{1}{2}a{{(n-2)}^{2}}\] \[=2a(n-1)\] Acceleration\[a=\frac{\upsilon }{n}\] \[(\because t=ns)\] Displacement in last \[2s=\frac{2\upsilon (n-1)}{n}\]You need to login to perform this action.
You will be redirected in
3 sec