question_answer

Number of isomers possible for\[{{C}_{4}}{{H}_{8}}O\]is:

A)  3               

B)  4

C)  5                

D)  6

Correct Answer: D

Solution :

 There are 6 isomers possible for the compounds having molecular formula\[{{C}_{4}}{{H}_{8}}O,\]which are as follows: \[\underset{(i)}{\mathop{C{{H}_{3}}C{{H}_{2}}\overset{\begin{smallmatrix}  O \\  |\,\,| \end{smallmatrix}}{\mathop{C}}\,C{{H}_{3}},}}\,\] \[\underset{(ii)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO,}}\,\] and \[\underset{(vi)}{\mathop{C{{H}_{2}}=CHC{{H}_{2}}C{{H}_{2}}OH}}\,\]