A) less than \[\omega \]
B) equal to \[\omega \]
C) equal to \[2\omega \]
D) infinitely large
Correct Answer: D
Solution :
For equilibrium of body \[mg=2Tcos\theta \] \[\therefore \] \[T=\frac{mg}{2\cos \theta }\] For the string to be horizontal, \[\theta \to 90{}^\circ \] \[\therefore \] \[T=\frac{mg}{2\cos 90}\Rightarrow T\to \infty \]You need to login to perform this action.
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