A) \[[ML{{T}^{-1}}A]\]
B) \[[{{M}^{2}}L{{T}^{-2}}{{A}^{-1}}]\]
C) \[[M{{T}^{-2}}{{A}^{-1}}]\]
D) none of these
Correct Answer: C
Solution :
\[\overrightarrow{F}=q\overrightarrow{v}\times \overrightarrow{g}\] or \[F=q\upsilon B\sin \theta \] \[\therefore \] \[[B]=\left[ \frac{F}{q\upsilon } \right]=\frac{ML{{T}^{-2}}}{[AT][L{{T}^{-1}}]}\] \[=[M{{T}^{-2}}{{A}^{-1}}]\]You need to login to perform this action.
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