A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) 3
D) 2
Correct Answer: A
Solution :
Specific heat of water\[=4200\text{ }J/kg-K\] Specific latent heat of fusion \[=3.36\times {{10}^{5}}J/kg\] Specific latent heat of vapourisation \[=22.68\times {{10}^{5}}J/kg\] \[=X\times {{10}^{-3}}\times 22.68\times {{10}^{5}}\] \[=Y\times {{10}^{-3}}\times 3.36\times {{10}^{5}}+Y\times {{10}^{-3}}\times 4200\times 100\] \[\therefore \] \[\frac{X}{Y}=\frac{7.56}{22.68}=\frac{1}{3}\]You need to login to perform this action.
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