A) \[-1.86{}^\circ C\]
B) \[1.86{}^\circ C\]
C) \[-3.92{}^\circ C\]
D) \[2.42{}^\circ C\]
Correct Answer: A
Solution :
Molality of cane sugar solution \[=\frac{342}{342\times 1}=1\,m\] We know that\[\Delta {{T}_{f}}={{K}_{f}}.m\] \[=1.86\times 1\] \[=1.86{}^\circ \] Hence, freezing point of solution \[=0.00-(1.86)=-1.86{}^\circ C\]You need to login to perform this action.
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