A) \[9g\]
B) \[6g\]
C) \[3g\]
D) \[0.3g\]
Correct Answer: C
Solution :
We know that, w (mass of solute) \[=\frac{m\times \Delta {{T}_{f}}\times W}{1000\times {{K}_{f}}}\] \[m=\]mol. wt. of urea (60) \[\Delta {{T}_{f}}=0.186{}^\circ C\] \[{{K}_{f}}=1.86{}^\circ ,W=500\,g\] \[=\frac{60\times 0.186\times 500}{1000\times 1.86}\] \[=3g\]You need to login to perform this action.
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