A) \[MgC{{l}_{2}}\]
B) \[SnC{{l}_{4}}\]
C) \[AlC{{l}_{3}}\]
D) \[NaCl\]
Correct Answer: C
Solution :
\[AlC{{l}_{3}}\]is a Lewis acid because it is electron deficient species.You need to login to perform this action.
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