A) \[\frac{2Bqd}{m}\]
B) \[\frac{Bqd}{m}\]
C) \[\frac{Bqd}{2m}\]
D) \[\frac{Bqm}{d}\]
Correct Answer: B
Solution :
The charged particle bends in a circle of radius r. \[Bqv\sin \frac{\pi }{2}=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \] \[r=\frac{mv}{Bq}\] The particle does not hit the plate if \[r\le d\] Or \[\frac{mv}{Bq}\le d\] Or \[v\le \frac{Bqd}{m}\] \[\therefore \] \[{{v}_{\max }}\le \frac{Bqd}{m}\]You need to login to perform this action.
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