A) 60 unit
B) \[40\sqrt{2}\]unit
C) zero
D) 7.5 unit
Correct Answer: A
Solution :
Momentum of the particle = mass\[\times \]velocity \[=(5)\times (3\sqrt{2})=15\sqrt{2}\] The direction of momentum in the XOY plane is given by \[y=x+4\] Slope of the line\[=1=tan\text{ }\theta \] i.e., \[\theta =45{}^\circ \] Intercept of its straight line = 4 Length of the perpendicular z from the origin of the straight line \[=4\sin 45{}^\circ =\frac{4}{\sqrt{2}}=2\sqrt{2}\] Angular momentum = momentum\[\times \]perpendicular length \[=15\sqrt{2}\times 2\sqrt{2}=60\,unit\]You need to login to perform this action.
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