A) \[60{{\pi }^{2}}m/{{s}^{2}}\]
B) \[80{{\pi }^{2}}m/{{s}^{2}}\]
C) \[120{{\pi }^{2}}m/{{s}^{2}}\]
D) \[144{{\pi }^{2}}m/{{s}^{2}}\]
Correct Answer: D
Solution :
Maximum acceleration of particle \[=a{{\omega }^{2}}=a{{(2\pi f)}^{2}}\] \[=4a{{\pi }^{2}}{{f}^{2}}\] \[=4\times 0.01\times {{\pi }^{2}}\times {{(60)}^{2}}\] \[=144\text{ }{{\pi }^{2}}m/{{s}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
